Question

alguém pra mim ajudar:)?​

Answer 1

Resposta:

Racionalizar

$A)~~\dfrac{1\sqrt{2} }{\sqrt{2} .\sqrt{2} }=\dfrac{\sqrt{2} }{\sqrt{4} }=\boxed{\dfrac{\sqrt{2} }{2}}$

$B)~~\dfrac{2\sqrt{3} }{\sqrt{3} .\sqrt{3} }=\dfrac{2\sqrt{3} }{\sqrt{9} }=\boxed{\dfrac{2\sqrt{3} }{3}}$

$C)~~\dfrac{4\sqrt{2} }{2.\sqrt{2} .\sqrt{2} }={\dfrac{4\sqrt{2} }{2\sqrt{4} }=\dfrac{4\sqrt{2} }{2.2}=\dfrac{4\sqrt{2} }{4}=\boxed{\sqrt{2} }$