Question

alguém pra ajudar



preciso de ajuda nesse trabalho de matemática para ontem, por favor alguma alma bondosa​

Answer 1

Resposta:

Explicação passo a passo:

1)

a)

$A +B-C = \left[\begin{array}{ccc}3\\2\\6\end{array}\right] +\left[\begin{array}{ccc}-2\\-1\\4\end{array}\right] -\left[\begin{array}{ccc}5\\0\\3\end{array}\right] = \left[\begin{array}{ccc}-4\\1\\7\end{array}\right]$

b)

$A-B+C=\left[\begin{array}{ccc}3\\2\\6\end{array}\right] -\left[\begin{array}{ccc}-2\\-1\\4\end{array}\right] +\left[\begin{array}{ccc}5\\0\\3\end{array}\right] =\left[\begin{array}{ccc}10\\3\\5\end{array}\right]$

c)

$A-B-C=\left[\begin{array}{ccc}3\\2\\6\end{array}\right] -\left[\begin{array}{ccc}-2\\-1\\4\end{array}\right] -\left[\begin{array}{ccc}5\\0\\3\end{array}\right] =\left[\begin{array}{ccc}0\\3\\-1\end{array}\right]$

2)

a)

$\left[\begin{array}{ccc}x\\y\\z\end{array}\right] +\left[\begin{array}{ccc}y\\2\\4\end{array}\right] =\left[\begin{array}{ccc}15\\9\\10\end{array}\right]$

$x+y = 15\\y+z = 9\\z+4 = 10\\\\z = 6\\y = 3\\x=12$

b)

$\left[\begin{array}{ccc}x&y\\3&2z\end{array}\right] +\left[\begin{array}{ccc}x&3\\t&z\end{array}\right] =\left[\begin{array}{ccc}12&4\\-1&9\end{array}\right]$

$2x = 12\\3+y = 4\\3+t = -1\\3z = 9\\\\x = 6\\y = 1\\z = 3\\t = -4$

3)

$\left[\begin{array}{ccc}7\\9\\8\end{array}\right]$

4)

$-7A = \left[\begin{array}{ccc}21&28\\7&-70\\-14&-35\end{array}\right]$

$4B = \left[\begin{array}{ccc}-8&-20\\4&-24\\0&-28\end{array}\right]$