Question

Alguem por favor poderia resolver essas operações com numeros complexos? A) (3 - 2i) + (5 + 6i) B) (4 - 3i) - (7 + 2i) C) (8 + 2i) . (7 + i) D) (6 + 2i) : (2 - 3i)

Answer 1

Explicação passo-a-passo:

a)

$\sf (3-2i)+(5+6i)$

$\sf =3-2i+5+6i$

$\sf =3+5-2i+6i$

$\sf =8+4i$

b)

$\sf (4-3i)-(7+2i)$

$\sf =4-3i-7-2i$

$\sf =4-7-3i-2i$

$\sf =-3-5i$

c)

$\sf (8+2i)\cdot(7+i)$

$\sf =56+8i+14i+2i^2$

$\sf =56+22i+2\cdot(-1)$

$\sf =56+22i-2$

$\sf =54+22i$

d)

$\sf \dfrac{6+2i}{2-3i}$

$\sf =\dfrac{6+2i}{2-3i}\cdot\dfrac{2+3i}{2+3i}$

$\sf =\dfrac{12+18i+4i+6i^2}{4^2^2-(3i)^2}$

$\sf =\dfrac{12+22i+6\cdot(-1)}{4-9i^2}$

$\sf =\dfrac{12+22i-6}{4-9\cdot(-1)}$

$\sf =\dfrac{6+22i}{4+9}$

$\sf =\dfrac{6}{13}+\dfrac{22i}{13}$