Question

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Answer 1

catetos

a = 4 cm

b = 3 cm

C = Va^2 + b^2

C = V (4)^2 + (3)^2

C = V 16 + 9

C = V25

C = 5 cm

area da base

Ab = ax b

.2

Ab = 4 x 3

.2

Ab = 12

2

Ab = 6 cm^2

area lateral

h = 10 cm

Al = (axh)+(bxh)+(cxh)

Al=h(a+b+c)

Al = 10 (4+3+5)

Al = 10 (7+5)

Al = 10 (12)

Al = 120 cm^2

area total

At = 2Ab + Al

At = 2(6) + 120

At = 12 + 120

At = 132 cm^2

volume

V = Abx h

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RESPONDERAl = 10 (4+3+5)

Al = 10 (7+5)

AI = 10 (12)

Al = 120 cm^2

area total

At = 2Ab + Al

At = 2(6) + 120

At = 12 + 120

At = 132 cm^2

volume

V = Ab x h

V = 6 x 10

V = 60 cm^3