Question

Alguém poderia me ajudar nesta questão?

Answer 1

a)

$f(-1)=-(-1)^2 +2(-1)\\f(-1)=-(1)-2\\f(-1)=-1-2\\f(-1)=-3\\f(1/2)=-(1/2)^2+2(1/2)\\f(1/2)=-(1/4)+2/2\\f(1/2)=-1/4+4/4\\f(1/2)=3/4$

b)

$g(0)=0/0^2-1\\g(0)=0/-1\\g(0)=0\\\\g(2)=2/2^2-1\\g(2)=2/4-1\\g(2)=2/3\\\\g(\sqrt{2} )= \sqrt{2}/(\sqrt{2})^2-1\\g(\sqrt{2})=\sqrt{2}/2-1\\g(\sqrt{2})=\sqrt{2}$

c)

$[f(a+b)-f(a-b)]/ab\\(af+bf-af+bf)/ab\\2bf/ab\\\\f(2bf/ab)=(2bf/ab)^2\\f(2bf/ab)=(2bf)^2/(a.b)^2\\f(2bf/ab)=4(b.f)^2/(a.b)^2$

d)$[f(a+b)-f(a-b)]/ab\\(af+bf-af+bf)/ab\\2bf/ab\\\\f(2bf/ab) = 3(2bf/ab)+1\\f(2bf/ab) = 6bf/ab+1\\f(2bf/ab) =6bf/ab +ab/ab\\f(2bf/ab) =(6bf+ab)/ab$

Espero muito ter ajudado