Matemática, perguntado por assmel17, 8 meses atrás

Alguém poderia me ajudar nessas questões?​

Anexos:

Soluções para a tarefa

Respondido por JAlves021
1

Resposta:

1)Basta somarmos os elementos correspondentes:

C=\left[\begin{array}{cc}3&4\\5&1\end{array}\right] + D= \left[\begin{array}{cc}0&2\\3&4\end{array}\right] \\\\C+D= \left[\begin{array}{cc}3&6\\8&5\end{array}\right]

2) Para calcularmos determinantes basta multiplicarmos a digonal principal e a diagonal secundaria, e subtrairmos.

\left[\begin{array}{ccc}6&4\\8&6\end{array}\right] \\\\6*6 - 8*4\\36-32=4\\DetB= 4

3)

A=\left[\begin{array}{ccc}5&7\\2&4\end{array}\right] B=\left[\begin{array}{ccc}3&6\\2&1\end{array}\right]\\\\\\A) A+B= \left[\begin{array}{ccc}8&13\\4&5\end{array}\right] \\\\\\B)A-B=\left[\begin{array}{ccc}2&1\\0&3\end{array}\right] \\\\\\C) A*B =\left[\begin{array}{ccc}15&42\\4&4\end{array}\right] \\\\

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