Question

Alguém poderia me ajudar nessas inequações? Ficarei muito grato!

a) 6x-7>3x+2

b) $2x+5x-8\geq -3+4x$

c) 5x+(7+4)>4x+6

d) $3(x-2)+3\leq 4(x+1)-4$

e) $\frac{x-1}{2}-\frac{3x-2}{3}\leq \frac{1+x}{4}$

f) $3(2x-3)-\frac{3(2-x)}{2}\ \textgreater \ 3$

g) $\frac{2x-3}{3}\ \textless \ \frac{4-x}{6}+\frac{2-3x}{2}$

h) $\frac{x-4}{3}-\frac{2(3-2x)}{3}\leq 2x$

Answer 1

A) 6x - 7 > 3x +2
6x - 3x > 2 + 7
3x > 9
x > 3

B) 2x+5x−8≥−3+4x 
7x - 8 ≥ - 3 + 8
7x - 4x ≥ - 3 + 8
3x ≥ 5
x ≥ 5/3

C) 5x+(7+4)>4x+6
5x+11>4x6
5x-4x>6-11
x>-5

D) 3(x−2)+3≤4(x+1)−4 
3x-6+3≤4x+4-4
3x-3≤4x
3x-4x≤ 3
-x≤ 3
x≥-3

E) ) \frac{x-1}{2}-\frac{3x-2}{3}\leq \frac{1+x}{4}​2​​x−1​​−​3​​3x−2​​≤​4​​1+x​​ 
6(x-1) -4 (3x-2) ≤ 3 (1+x)
6x -6-12x+8≤ 3+3x
-6x+2≤ 3+3x
-6x-3x≤ 3-2
-9x≤1
x≤-1/9