Matemática, perguntado por rafael93545412p7i1ud, 1 ano atrás

Alguém poderia me ajudar com matriz tô embolado com os sinais?

Anexos:

Soluções para a tarefa

Respondido por Rich0031
1
  \left[\begin{array}{ccc}2&- 1\\- 2&0\end{array}\right] +   \left[\begin{array}{ccc}1&- 5\\2&- 2\end{array}\right] =   \left[\begin{array}{ccc}3&- 6\\0&- 2\end{array}\right]  \\ \\ \\   \left[\begin{array}{ccc}- 7&5\\3&- 1\\4&6\end{array}\right] +   \left[\begin{array}{ccc}4&- 8\\- 5&- 2\\- 3&1\end{array}\right] =   \left[\begin{array}{ccc}- 3&- 3\\- 2&- 3\\1&7\end{array}\right]

  \left[\begin{array}{ccc}- 1&3\\- 2&- 2\end{array}\right] -    \left[\begin{array}{ccc}6&7\\1&1\end{array}\right] +   \left[\begin{array}{ccc}- 2&- 5\\- 4&- 1\end{array}\right] \\ \\   \left[\begin{array}{ccc}- 1&3\\- 2&- 2\end{array}\right] -   \left[\begin{array}{ccc}4&2\\- 3&0\end{array}\right] =   \left[\begin{array}{ccc}- 5&1\\1&- 2\end{array}\right]

 \left[\begin{array}{ccc}2&5&- 3\\- 7&- 1&1\end{array}\right] -   \left[\begin{array}{ccc}- 1&- 5&- 4\\11&- 2&- 8\end{array}\right] = \left[\begin{array}{ccc}3&10&7\\- 18&3&9\end{array}\right] \\ \\ \\   \left[\begin{array}{ccc}10&20&30\\- 9&- 5&17\end{array}\right] -   \left[\begin{array}{ccc}- 15&- 12& - 25\\11&- 18&- 22\end{array}\right] =   \left[\begin{array}{ccc}25&32&55\\- 20&13&39\end{array}\right]

rafael93545412p7i1ud: obg me ajudou muuto
rafael93545412p7i1ud: muito
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