Question

Alguém poderia me ajudar a resolver esses sistemas?(método da substituição)
{x+4y=-3
{-3x-y=-24

{x+y=-1
{x+5y=3

{x-5y=6
{2x+y=1

{2x+y=4
{x-2y=-3

{3x-y=5
{2x+3y=18

{x-5y=6
{5x+2y=3

Answer 1

{x+4y=-3
{-3x-y=-24
x=-3-4y
-3(-3-4y)-y=-24
9+12y-y=-24
12y-y=-24-9
11y=-33
y=-33/11
y=-3
x=-3-4×-3
x=-3+12
x=9

{x+y=-1
{x+5y=3
x=-1-y
-1-y+5y=3
-y+5y=3+1
4y=4
y=4/4
y=1
x=-1-1
x=-2

{x-5y=6
{2x+y=1
x=6+5y
2(6+5y)+y=1
12+10y+y=1
10y+y=1-12
11y=11
y=11\11
y=1
x=6+5×1
x=6+5
x=11

{2x+y=4
{x-2y=-3
y=4-2x
x-2(4-2x)=-3
x-8+4x=-3
x+4x=-3+8
5x=5
x=5/5
x=1
y=4-2×1
y=4-2
y=2

{3x-y=5
{2x+3y=18
-y=5-3x
y=-5+3x
2x+3(-5+3x)=18
2x-15+9x=18
2x+9x=18+15
11x=33
x=33/11
x=3
y=-5+3×3
y=-5+9
y=4

{x-5y=6
{5x+2y=3
x=6+5y
5(6+5y)+2y=3
30+25y+2y=3
25y+2y=3-30
27y=-27
y=-27/27
y=-1
x=6+5×-1
x=6-5
x=1

espero ter ajudado ♡♥