Question

Alguém poderia me ajudar

Answer 1

Resposta e Explicação passo a passo:

$a)4x=8\\x=\frac{8}{4}\\x=2$

$b)3x-2=7\\3x=7+2\\3x=9\\x=\frac{9}{3}\\x=3$

$c)-2x-4=8\\-2x=8+4\\-2x=12\\x=\frac{12}{-2}\\x=-6$

$d)3x-4=x+8\\3x-x=8+4\\2x=12\\x=\frac{12}{2}\\x=6$

$e)3(2x+3)=2(x+5)\\6x+9=2x+10\\6x-2x=10-9\\4x=1\\x=\frac{1}{4}=0,25$