Question

Alguém pode resolver?

Answer 1

4x^2-676x=0
delta=b^2-4ac
delta=(-676)^2-4.4.0
delta=456976-0
delta=456976
x=-b-/+ raiz de delta/2a
x=-(-676)- 676/2.4
x=676-676/8
x=0/8
x=0
x=-(-676)+676/2.4
x=676+676/8
x=1352/8
x=169