Question

alguém pode me explicar por q deu 4?

Answer 1

Olá


$\displaystyle \mathsf{2~+~ \frac{\left( \frac{ \sqrt{16}~\cdot~ 8}{2} \right)^ \frac{1}{2}~\cdot~2^{-1} }{cos(2\pi)} ~=~4}\\\\\\\\\mathsf{ \sqrt{16}=4 }\\\\\\\\ \mathsf{2~+~ \frac{\left( \frac{ 4~\cdot~ 8}{2} \right)^ \frac{1}{2}~\cdot~2^{-1} }{cos(2\pi)} ~=~4}\\\\\\\\ \mathsf{2~+~ \frac{\left( \frac{ 32}{2} \right)^ \frac{1}{2}~\cdot~2^{-1} }{cos(2\pi)} ~=~4}\\\\\\\\ \mathsf{2~+~ \frac{\left( 16 \right)^ \frac{1}{2}~\cdot~2^{-1} }{cos(2\pi)} ~=~4}\\\\\\\\\mathsf{16^{ \frac{1}{2} }~=~ \sqrt{16} ~=~4}$


$\displaystyle \mathsf{2~+~ \frac{4~\cdot~2^{-1} }{cos(2\pi)} ~=~4}\\\\\\\mathsf{2^{-1}~=~ \frac{1}{2} }\\\\\\\\ \mathsf{4\cdot \frac{1}{2} ~=~2}\\\\\\\mathsf{2~+~ \frac{4\cdot \frac{1}{2} }{cos(2\pi)} ~=~4}\\\\\\\\ \mathsf{2~+~ \frac{2 }{cos(2\pi)} ~=~4}\\\\\\\\\mathsf{cos(2\pi)=1}\\\\\\\\ \mathsf{2~+~ \frac{2 }{1} ~=~4}\\\\\\\boxed{\mathsf{2+2=4}}\qquad\qquad\checkmark$





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