Alguém pode me da uma força nessa questão?
Encontre o divergente e o rotacional dos campo vetorial:
V(x, y, z)= 3xi + 2yj - 3zk
Soluções para a tarefa
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Hallemos div V

Hallemos el rotacional

Hallemos el rotacional
geylson1:
¡muy agradecido!
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