Question

alguém pode me ajudar por favor

Answer 1

$A=\left[\begin{array}{cc}a11&a12\\a21&a22\end{array}\right]$
$Aij = 3i-2j \\ a11 = 3.1 - 2.1 = 3-2 = 1 \\ a12 = 3.1 - 2.2= 3-4 = -1 \\ a21 = 3.2 - 2.1 = 6-2 = 4 \\ a22 = 3.2 - 2.2 = 6-4 = 2$
$A = \left[\begin{array}{cc}1&-1\\4&2\end{array}\right]$
$B = \left[\begin{array}{cc}b11&b12\\b21&b22\end{array}\right]$
 $Bij = (3i)^{2}$
$b11 = (3.1)^{2} =3^{2}=9$
$b12 = (3.1)^{2} =3^{2}=9$
$b21 = (3.2)^{2} =6^{2}=36$
$b22 = (3.2)^{2} =6^{2}=36$ 
$B = \left[\begin{array}{cc}9&9\\36&36\end{array}\right]$
$A-B = \left[\begin{array}{cc}-8&-10\\-32&-34\end{array}\right]$
$A+B = \left[\begin{array}{cc}10&8\\40&38\end{array}\right]$