Question

alguém pode me ajudar pelo menos no primeiro exercício? help!!!

Answer 1

Resposta:

Explicação passo-a-passo:

1) a) [ m        7]    =   [ 8       7 ]        

      [ n         -1]         [  9      -1 ]

    m = 8

    n = 9

b)  [ m   2n ]    =  [ 4 -n     2 ]

     [ 9      -1  ]        [  9       -1  ]

2n = 2

n = 2    

      2

  n = 1

m  = 4 - n

m = 4 - 1

m = 3

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2)

   a)    (2)     +   (1 )       =  ( 3 )

          (8)          (2 )          ( 10 )

  b)     (10    5 )       +       ( 2     -6 )    =   ( 12   - 1 )

          (- 1    0 )                (-3       7 )         (-4      7 )

 c)  ( 7   0 )  +  ( 1   3)  =  ( 8   3 )

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3)   ( a    b )     +   ( 2  - 1 )    =  (  5  8  )   +    ( 1     0  )    +  (  -1     -6  )

     ( 6     c )         ( 3      4 )      (   4   0 )        ( 3     2  )       (   2     5  )

a + 2 =  5 + 1 - 1

a = 5 + 1 - 1 - 2

a = 3

b - 1 =  8 + 0  - 6

b = 8 + 0 - 6 +1

b = 3

c +  4  =  0  + 2  + 5

c = 0 + 2 + 5 - 4

c = 3

Answer 2

Resposta:

Ver abaixo

Explicação passo-a-passo:

1a) m = 8 e n = 9

1b) 2n = 2 --> n = 2/2 --> n = 1

m = 4 - n --> m = 4 - 1 --> m = 3

2a)

$\left(\begin{array}{c}2\\8\end{array}\right)+\left(\begin{array}{c}1\\2\end{array}\right)=\left(\begin{array}{c}2+1\\8+2\end{array}\right)=\left(\begin{array}{c}3\\10\end{array}\right)$

2b)

$\left(\begin{array}{cc}10&5\\-1&0\end{array}\right)+\left(\begin{array}{cc}2&-6\\-3&7\end{array}\right)=\left(\begin{array}{cc}10+2&5-6\\-1-3&0+7\end{array}\right)=\left(\begin{array}{cc}12&-1\\-4&7\end{array}\right)$

2c)

$\left(\begin{array}{cc}7&0\end{array}\right)+\left(\begin{array}{cc}1&3\end{array}\right)=\left(\begin{array}{cc}7+1&0+3\end{array}\right)=\left(\begin{array}{cc}8&3\end{array}\right)$

3)

$\left(\begin{array}{cc}a&b\\6&c\end{array}\right)+\left(\begin{array}{cc}2&-1\\3&4\end{array}\right)=\left(\begin{array}{cc}5&8\\4&0\end{array}\right)+\left(\begin{array}{cc}1&0\\3&2\end{array}\right)+\left(\begin{array}{cc}-1&-6\\2&5\end{array}\right)$

$\left(\begin{array}{cc}a&b\\6&c\end{array}\right)+\left(\begin{array}{cc}2&-1\\3&4\end{array}\right)=\left(\begin{array}{cc}5+1-1&8+0-6\\4+3+2&0+2+5\end{array}\right)$

$\left(\begin{array}{cc}a&b\\6&c\end{array}\right)+\left(\begin{array}{cc}2&-1\\3&4\end{array}\right)=\left(\begin{array}{cc}5&2\\9&7\end{array}\right)$

$\left(\begin{array}{cc}a&b\\6&c\end{array}\right)=\left(\begin{array}{cc}5&2\\9&7\end{array}\right)-\left(\begin{array}{cc}2&-1\\3&4\end{array}\right)=\left(\begin{array}{cc}5-2&2-(-1)\\9-3&7-4\end{array}\right)=\left(\begin{array}{cc}3&3\\6&3\end{array}\right)$

Logo, a = b = c = 3

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