Question

Alguém pode me ajudar nesse teste de matemática?​

Answer 1

Resposta:

Explicação passo-a-passo:

1) a)∛$m^{7}$ = $m^{\frac{7}{3} }$

  b)$\sqrt[3]{x^{8} } = x^{\frac{8}{3} }$

  c)$\sqrt{9^{20} } = 9^{10}=3^{20}$

  d)$\sqrt[5]{a^{6} } = a^{\frac{6}{5} }$

2)a)$\frac{\sqrt[3]{\sqrt{12} }X\sqrt{\sqrt[3]{15}}  }{\sqrt[6]{18} }=\frac{\sqrt[6]{12}X\sqrt[6]{15}}{\sqrt[6]{18}} =\frac{\sqrt[6]{180}}{\sqrt[6]{18}} =\sqrt[6]{10}$

  b) $\frac{\sqrt[5]{\sqrt{a^{5} } }X\sqrt{\sqrt[5]{a^{8} } }  }{\sqrt[10]{a^{2} } }=\frac{\sqrt[10]{a^{5} }X\sqrt[10]{a^{8} }  }{\sqrt[10]{a^{2} } }=\frac{\sqrt[10]{a^{13} } }{\sqrt[10]{a^{2} } }=\sqrt[10]{a^{11} }$      

3) a) $\sqrt{50}+\sqrt{18}-\sqrt{8}=5\sqrt{2}+3\sqrt{2}-2\sqrt{2}=6\sqrt{2}$

    b)√75 +2√27-√300+√48=5√3+6√3-10√3=√3

4) a)$2(3\sqrt{80} +\sqrt{20})=2(12\sqrt{5}  +2\sqrt{5})=2.(14\sqrt{5})=28\sqrt{5}$

   b)$\sqrt{8}+\sqrt{32}+\sqrt{18}=2\sqrt{2}+4\sqrt{2}+3\sqrt{2}=9\sqrt{2}$