Question

Alguem pode me ajudar nessas questões?

Answer 1

a³+3a²b+3ab²+b + a³-3a²b-b³=
2a³+6ab²=
2a(a+3b²)=
2a . 1/a= 2

(x²+y²) (x²-y²)+2x(x²y - y³)=
(x²+y²) (x+y) (x-y) + 2xy(x²-y²)=
(x²+y²)(x+y)(x-y) +2xy(x+y)(x-y)=
(x²+y²+2xy) (x+y)(x-y)=
(x + y)² (x+y)(x-y)=
(x + y)³ (x-y)