Question

Alguém pode me ajudar nessa questão

Answer 1

$x^{2} -x-30=0$

Δ = $(-1)^{2} -4(-30)$

Δ = $(-1)^{2} +120$

Δ = $1+120$

Δ = $121$

$x_{1,2}=\frac{1\±121}{2}$

$x_{1,2} = \frac{1\±11}{2}$

$x'= \frac{1+11}{2}$

$x'= \frac{12}{2}$

$x'=6$

$x''= \frac{1-11}{2}$

$x''= \frac{-10}{2}$

$x''=-5$