Alguem pode me ajudar em: Log 1/27 na base9?
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Bom dia!
Solução!
![log_{9} \frac{1}{9} \\\\\\
log_{9} \frac{1}{9} =x\\\\\\
\frac{1}{9}=9^{x}\\\\\\
\frac{1}{3^{2} }=(3^{2})^{x}\\\\\\
3^{-2}= (3^{2})^{x}\\\\\
-2=2x\\\\\
x= \dfrac{-2}{2}\\\\\
x=-1\\\\\\\\\\\\
\boxed{Resposta: x=-1}](https://tex.z-dn.net/?f=log_%7B9%7D+%5Cfrac%7B1%7D%7B9%7D+%5C%5C%5C%5C%5C%5C+%0Alog_%7B9%7D+%5Cfrac%7B1%7D%7B9%7D+%3Dx%5C%5C%5C%5C%5C%5C+%0A+%5Cfrac%7B1%7D%7B9%7D%3D9%5E%7Bx%7D%5C%5C%5C%5C%5C%5C%0A+%5Cfrac%7B1%7D%7B3%5E%7B2%7D+%7D%3D%283%5E%7B2%7D%29%5E%7Bx%7D%5C%5C%5C%5C%5C%5C%0A%0A3%5E%7B-2%7D%3D+%283%5E%7B2%7D%29%5E%7Bx%7D%5C%5C%5C%5C%5C%0A-2%3D2x%5C%5C%5C%5C%5C%0Ax%3D+%5Cdfrac%7B-2%7D%7B2%7D%5C%5C%5C%5C%5C%0Ax%3D-1%5C%5C%5C%5C%5C%5C%5C%5C%5C%5C%5C%5C%0A%5Cboxed%7BResposta%3A+x%3D-1%7D++%0A+++++ "log_{9} \frac{1}{9} \\\\\\
log_{9} \frac{1}{9} =x\\\\\\
\frac{1}{9}=9^{x}\\\\\\
\frac{1}{3^{2} }=(3^{2})^{x}\\\\\\
3^{-2}= (3^{2})^{x}\\\\\
-2=2x\\\\\
x= \dfrac{-2}{2}\\\\\
x=-1\\\\\\\\\\\\
\boxed{Resposta: x=-1}")
Bom dia!
Bons estudos!
Solução!
Bom dia!
Bons estudos!
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