Question

Alguém pode me ajudar determime a soma sos polimonios (3/5a+2/3b-3c)+(-2a+3/4b+1/2c)?

Answer 1

Explicação passo-a-passo:

$(\frac{3}{5}a+\frac{2}{3}b-3c)+(-2a+\frac{3}{4}b+\frac{1}{2}c)$

$\frac{3}{5}a+\frac{2}{3}b-3c-2a+\frac{3}{4}b+\frac{1}{2}c$

$\frac{3}{5}a-2a+\frac{2}{3}b+\frac{3}{4}b-3c+\frac{1}{2}c$

$(\frac{3}{5}-2)a+(\frac{2}{3}+\frac{3}{4})b+(-3+\frac{1}{2})c$

$(\frac{3-10}{5})a+(\frac{8+9}{12})b+(\frac{-6+1}{2})c$

$-\frac{7}{5}a+\frac{17}{12}b-\frac{5}{2}c$