Question

Alguém pode me ajudar com a 14?
E com a 4?

Answer 1

f(x) = 3x - 1/2
f(1/3) = 3.1/3 - 1/2 =
3/3 - 1/2 = 1 - 1/2 = 3/2

g(x) = 2x/5 + 1
g(-2) = 2.(-2)/5 + 1
g(-2) = -4/5 + 1
g(-2) = -4/5 + 5/5
g(-2) = 1/5

f(1/3) - g(-2) = 
3/2 - 1/5 = 
15/10 - 2/10 = 13/10

Answer 2

4. f': $x = \frac{y + 1}{2y + a} --\ \textgreater \ 2xy + xa = y + 1--\ \textgreater \ 2xy -y = 1 - xa ;$, $--\ \textgreater \ y ( 2x - 1) = 1 - xa --\ \textgreater \ y = \frac{1 - xa}{2x - 1}$; comparando a = 3; 14) $3. \frac{1}{3} - \frac{1}{2} - ( \frac{2. (-2)}{5 } + 1) = 1 - \frac{1}{2} - (- \frac{4}{5} + 1) = \frac{1}{2} - ( \frac{1}{5} )= \frac{5 - 2}{10} = \frac{3}{10}$