Question

ALGUÉM PODE ME AJUDAR AGORA PURFAVOR 30 PONTOS

Answer 1

1 →
$(2^9 \div ( 2^2 \times 2)^3 )^{-3} \\\\ (2^9 \div (2^3)^3 )^{-3} \\\\ ( 2^9 \div 2^9 )^{-3} \\\\ 1^{-3} = 1$

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2 →
${ (ab)^3 \times b^7 \times (a^3)^2 \over b^3 \times a^5} \\\\ { a^3b^3 \times b^7 \times a^6 \over a^5b^3 } \\\\ {a^9b^{10} \over a^5b^3} \\\\ a^4b^7$

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3 →
$\frac{( { - 5})^{2} - {3}^{2} + \left( { \frac{2}{3} } \right)^{0} }{ {3}^{ - 2} + \frac{1}{5} + \frac{1}{2} } \\ \\ \frac{25 - 9 + 1}{ \frac{1}{9} + \frac{7}{10} } \\ \\ \frac{17}{ \frac{73}{90} } = \frac{17 \times 90}{73} = \frac{1530}{73}$