Question

alguem pode me ajudar a RESPONDER essa atividade de matematica ?

Answer 1

LETRA a)

$\frac{\textsf{AB}}{\textsf{DE}} = \frac{\textsf{BC}}{\textsf{EF}} = \frac{\textsf{AC}}{\textsf{DF}}$

LETRA b)

$\frac{\textsf{AB}}{\textsf{DE}} = \frac{\textsf{BC}}{\textsf{EF}}$

LETRA c)

Dados do enunciado:

1) Sombra da estaca  = 1/4 altura da estaca.

$\textsf{EF} = \frac{\textsf{DE}}{4}$

2) BC = metade do comprimento da base  + sombra da pirâmide

$\textsf{BC} = \frac{110}{2}+57 = 112\textsf{m}$

Resolvendo:

$\frac{\textsf{AB}}{\textsf{DE}} = \frac{\textsf{BC}}{\textsf{EF}}\\\\\frac{\textsf{AB}}{\textsf{DE}} = \frac{\textsf{112}}{\frac{\textsf{DE}}{4}}\\\\\frac{\textsf{AB}}{\textsf{DE}} = 112 \times \frac{\textsf{4}}{\textsf{DE}}\\\\\frac{\textsf{AB}}{\textsf{DE}} = \frac{\textsf{448}}{\textsf{DE}}\\\\\textsf{AB} = \frac{\textsf{448}}{\textsf{DE}}\times \textsf{DE}\\\\\textsf{AB} = 448\textsf{m}$

A pirâmide tem 448 metros de altura.