Question

alguém pode me ajudar a resolver isso ?​

Answer 1

a)

$log_{5}5 \sqrt{5} = x \\ 5 \sqrt{5} = {5}^{x} \\ \sqrt{5. {5}^{2} } = {5}^{x} \\ \sqrt{ {5}^{3} } = {5}^{x} \\ {5}^{ \frac{3}{2} } = {5}^{x} \\ \\ \frac{3}{2} = x$

b)

$log_{ \frac{1}{9} } \sqrt{27} = x \\ \sqrt{27} = ( \frac{1}{9})^{x} \\ \sqrt{ {3}^{3} } = (\frac{1}{ {3}^{2} })^{x} \\ {3}^{ \frac{3}{2} } = (\frac{1}{3})^{2x} \\ (\frac{1}{3})^{ - \frac{3}{2} } = ( \frac{1}{3})^{2x} \\ - \frac{3}{2} = 2x \\ - \frac{3}{2.2} = x \\ \\ - \frac{3}{4} = x$