Question

alguém pode me ajudar a resolver a solucionar essa equação?

$-\frac{3}{5} x^{2} - \sqrt[3]{5} x = -2\sqrt[3]{5} x$

Answer 1

$\LARGE\tt{} - \dfrac{3}{5} {x}^{2} - \sqrt[3]{5x} = - 2 \sqrt[3]{5x} \\ \\ \LARGE\tt{} - \dfrac{ {3x}^{2} }{5} - \sqrt[3]{5x} = - 2 \sqrt[3]{5x} \\ \\ \LARGE\tt{} - \sqrt[3]{5x} + 2 \sqrt[3]{5x} = \dfrac{ {3x}^{2} }{5} \\ \\ \LARGE\tt{} \sqrt[3]{5x} = \dfrac{ {3x}^{2} }{5} \\ \\\LARGE\tt{} \dfrac{5}{3} \times \sqrt[3]{5x} = {x}^{2} \\ \\ \LARGE\tt{}5 \sqrt[3]{5x} = {3x}^{2} \\ \\\LARGE\tt{} 125 \times 5x = {27x}^{6} \\ \\ \LARGE\tt{}625x = {27x}^{6} \\ \\ \LARGE\tt{}625x - {27x}^{6} = 0 \\ \\ \LARGE\tt{}x \times \left(625 - {27x}^{5} \right) = 0 \\ \\\LARGE\tt{}x = 0 \\ \LARGE\tt{}625 - {27x}^{5} = 0 \\ \\ \LARGE\tt{}x = 0 \\ \\ \\ \LARGE\tt{}x = \dfrac{ \sqrt[5]{5625} }{3} \\ \\ \\ \LARGE\tt{} \boxed{ x_{1} =0 } \\ \\ \LARGE\tt{}\LARGE\tt{} \boxed{ x_{2} = \dfrac{ \sqrt[5]{5625} }{3} }$

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