Question

Alguém pode me ajudar?

Answer 1

Volume total = > 100 + 100 = 200 ml

BaCl²

M₁ * V₁ = M₂ * V₂

0.6 * 100 = M₂ * 200

60 = M₂ * 200

M₂ =  60 / 200

M₂ = 0.3 mol/l

Ba(NO₃)₂

0.4 * 100 = M₂ * 200

40 = M₂ * 200

M₂ = 40 / 200

M₂ = 0.2 mol/l

BaCl₂ ---> Ba + 2 + 2Cl - 1

Ba(NO₃) 2  --->  Ba + 2 + 2 NO₃-

[Ba+2] 0.3 + 0.2 = 0.5 mol/l

[Cl-] 2 * 0.3 = 0.6 mol/l

[NO₃-] 2 * 0.2 = 0.4 mol/l