Question

Alguém pode me ajudar?

(2.6-2³)²:2².3².[5²-(2³+6º)]:4=

Answer 1

$(2.6-2^3)^2:2^2.3^2.[5^2-(2^3+6^0)]:4 = (2.6-8)^2:2^2.3^2.[5^2-8+1]:4 = (12-8)^2:2^2.3^2.[25-8+1]: 4 = (4)^2:2^2.3^2.[26-8]:4 = 16:2^2.3^2.18:4 = 16:4.9.18:4 = 4.9.4,5 = 36.4,5 = 162 Bons estudos! :-)$

Answer 2

Resolva As potencias


$(2 \times 6 - {2}^{3} {)}^{2} \div {2 \times {3}^{2} }^{} \times ( {25}^{} - ( {8}^{} + {1}^{} ) \div 4 \\ (12 - 8 {)}^{2} \div {2}^{2} \times {3}^{2} \times (25 - (9)) \div 4 \\ {(4)}^{2} \div {2}^{2} \times {3}^{2} \times (25 - 9) \div 4 \\ 16 \div {6}^{2} \times (16) \div 4 \\ 16 \div 36 \times 16 \div 4 \\ \frac{16}{36} \times 16 \div 4 \\ \\ \frac{16}{36} \times 4 \\ \\ \frac{64}{36} \\ \\ 1.77778........$