Question

alguem pod responde essa jossa pra mim ????????????????

Answer 1

32)
$\sqrt{?} = 100$ ⇒ $? = 100^{2} =10000$

$\sqrt[3]{?} = -8$ ⇒ $? = (-8)^{3} = -512$

$\sqrt[?]{64} =4$ ⇒ $\sqrt[?]{ 2^{6} } = 2^{2}$ ⇒ $2^{ \frac{6}{?} } = 2^{2}$ ⇒ $\frac{6}{?} =2$ ⇒ $?=3$

$\sqrt[?]{64} =2$ ⇒ $\sqrt[?]{ 2^{6} } = 2^{1}$ ⇒ $2^{ \frac{6}{?} } = 2^{1}$ ⇒ $\frac{6}{?} =1$ ⇒ $?=6$

33)
$\sqrt{256} = \sqrt{ 2^{8} } = 2^{4} =16$

$\sqrt{729} = \sqrt{ 3^{6} } = 3^{3} =27$

$\sqrt[3]{343} = \sqrt[3]{ 3^{5} } =3 \sqrt[3]{9}$

$\sqrt[5]{1024} = \sqrt[5]{ 2^{10} } = 2^{2} =4$

$\sqrt{1296} = \sqrt{ 2^{4}. 3^{4} } = 2^{2}. 3^{2} =4.9=36$

$\sqrt{1089} = \sqrt{ 3^{2}. 11^{2} } = 3. 11 =33$

34)
$\sqrt{ 3^{8} } = 3^{4} =81$

$\sqrt[3]{ 10^{3} } =10$

$\sqrt{ 2^{4} } = 2^{2} =4$

$\sqrt{ 10^{6} } = 10^{3} =1000$

$\sqrt[3]{ 2^{9} } = 2^{3} =8$

$\sqrt[4]{ 5^{8} } = 5^{2} =25$

35)
$\sqrt[3]{3375} = \sqrt[3]{ 3^{3}. 5^{3} } =3.5=15$

$\sqrt[4]{4096} = \sqrt[4]{ 2^{12} } = 2^{3}= 8$

$5 \sqrt{196} = 5 \sqrt{ 2^{2} . 7^{2} } =5.2.7=70$

$-3 \sqrt{324} =-3 \sqrt{ 2^{2} . 3^{4} } =-3.2.9=-54$

$4 \sqrt[3]{216} =4 \sqrt[3]{ 2^{3} . 3^{3} } =4.2.3=24$

$\sqrt[3]{ 2^{6} . 3^{2} . 5^{3} } = 2^{2} .5 \sqrt[3]{ 3^{2} } =20 \sqrt[3]{9}$