Question

alguém pfvr me ajuda!!!​

Answer 1

Resposta:

a) x1= 6 ; x2= -6

b) x1= 10 ; x2= -10

c) x1= 7 ; x2= -7

Explicação passo-a-passo:

a) ∆= b² - 4ac

∆= 0² - 4.1.(-36)

∆= 0 + 144

∆= 144

x= -b +/- √∆ / 2a

x= 0 +/- √144 / 2.1

x= 0 +/- 12 / 2

x1= 0 + 12 / 2 = 12/2 = 6

x2= 0 - 12 / 2 = -12/2= -6

b) ∆= b² - 4ac

∆= 0² - 4.1.(-100)

∆= 0 + 400

∆= 400

x= -b +/- √∆ / 2a

x= 0 +/- √400 / 2.1

x= 0 +/- 20 / 2

x1= 0 + 20 / 2 = 20/2 = 10

x2= 0 - 20 / 2 = -20/2 = -10

c) ∆= b² - 4ac

∆= 0² - 4.1.(-49)

∆= 0 + 196

∆= 196

x= -b +/- √∆ / 2a

x= 0 +/- √196 / 2.1

x= 0 +/- 14 / 2

x1= 0 + 14 / 2 = 14/2 = 7

x2= 0 - 14 / 2 = -14/2= -7