Question

ALGUEM PELO AMOR DE DEUS




redução de termos semelhantes



a) –[x + (7 – x) – (5 + 2x)] =
b) { 9x – [ 4x – (x – y)- 5y] + y} =
c) (3a + 2m ) – [ ( a – 2m) – (6a + 2m)] =
d) 7x³- { 3x² - x – [ 2x – { 5x³ - 6x² ) – 4x ]} =
e) 2y – { 3y + [4y – (y – 2x) + 3x ] – 4x } + 2x =
f) 8y + { 4y – [ 6x – y- (4x – 3y) – y ] – 2x } =
g) 4x – { 3x + [ 4x – 3y – (6x – 5y ) – 3x ] – 6y}
h) 3x – { 3x – [3x – (3x –y) – y ] – y} - y
​

Answer 1

Olá!!!!!!!!

a) –[x + (7 – x) – (5 + 2x)] =

=−[x+(−x+7)−(2x+5)]=  

=−[7−(2x+5)]=

=2x−2

b) { 9x – [ 4x – (x – y)- 5y] + y}=

={9x−[(3x+y)−5y]+y}=  

={9x−[3x−4y]+y}=

={(6x+4y)+y}=

=6x+5y

c) (3a + 2m ) – [ ( a – 2m) – (6a + 2m)] =

=(3a+2m)−[−5a−4m]=  

=8a+6m

d) 7x³- { 3x² - x – [ 2x – { 5x³ - 6x² ) – 4x ]} =

=7x³−{(3x² −x)−[(−5x³+6x²+2x)−4x]}=  

=7x³−{(3x² −x)−[−5x³+6x²−2x]}=

=7x³−{5x³−3x² +x}=

=2x³+3x²−x

e) 2y – { 3y + [4y – (y – 2x) + 3x ] – 4x } + 2x =

=2y−{3y+[(3y+2x)+3x]−4x}+2x=  

=2y−{3y+[3y+5x]−4x}+2x=

=2y−{(6y+5x)−4x}+2x=

=2y−{6y+x}+2x=

=(−4y−x)+2x=

=−4y+x

f) 8y + { 4y – [ 6x – y- (4x – 3y) – y ] – 2x } =

=8y+{4y−[(−y+6x)−(−3y+4x)−y]−2x}=  

=8y+{4y−[(2y+2x)−y]−2x}=

=8y+{4y−[y+2x]−2x}=

=8y+{(3y−2x)−2x}=

=8y+{3y−4x}=

=11y−4x

g) 4x – { 3x + [ 4x – 3y – (6x – 5y ) – 3x ] – 6y}

=4x−{3x+[(−2x+2y)−3x]−6y}=  

=4x−{3x+[−5x+2y]−6y}=

=4x−{(−2x+2y)−6y}=

=4x−{−2x−4y}=

=6x+4y

h) 3x – { 3x – [3x – (3x –y) – y ] – y} - y

=3x−{3x−[y−y]−y}−y=  

=3x−{3x−[0]−y}−y=

=3x−{3x−y}−y=

=y−y=

=0

Espero ter te ajudado!!!!!!