Question

Alguém pede me ajudar

100x+80=120x-(40x-300)

Answer 1

$100x + 80 = 120x - (40x - 300) \\ 100x + 80 = 120x - 40x + 300 \\ 100x + 40x - 120x = 300 - 80 \\ 140x - 120x = 220 \\ 20x = 220 \\ x = \frac{220}{20 } \\ x = 11$


S = {11}

Answer 2

Olá, boa noite ☺

Resolução:

100x + 80 = 120x -(40x - 300)

100x + 80 = 120x - 40x + 300

100x - 120x + 40x = 300 - 80

20x = 220

x=220/20

x = 11

Bons estudos :)