Question

alguém mim ajuda porfravor ​

Answer 1

Resposta:

$\sqrt[x]{\sqrt{2} } =\sqrt[12]{2} \\ \\ \sqrt[x]{\sqrt[2]{2} } =\sqrt[12]{2} \\ \\ \sqrt[2x]{2} =\sqrt[12]{2} \\ \\ 2x=12\\ \\ x=\frac{12}{2} \\ \\ x=6$

$\sqrt[3]{\sqrt[y]{5} } =\sqrt[15]{5} \\ \\ \sqrt[3y]{5} =\sqrt[15]{5} \\ \\ 3y=15\\ \\ y=\frac{15}{3}\\ \\ y=5\\ \\ \\ Resposta:\\ \\ \\ x-y=6-5\\ \\ \\ x-y=1$