Question

alguém mi ajuda nessa pf


-6+√-6²-4•1•5 /2•1
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Answer 1

Explicação passo-a-passo:

x² - 6x + 5 = 0

• $\sf x'=\dfrac{-(-6)+\sqrt{(-6)^2-4\cdot1\cdot5}}{2\cdot1}$

$\sf x'=\dfrac{6+\sqrt{36-20}}{2}$

$\sf x'=\dfrac{6+\sqrt{16}}{2}$

$\sf x'=\dfrac{6+4}{2}$

$\sf x'=\dfrac{10}{2}$

$\sf x'=5$

• $\sf x"=\dfrac{-(-6)-\sqrt{(-6)^2-4\cdot1\cdot5}}{2\cdot1}$

$\sf x"=\dfrac{6-\sqrt{36-20}}{2}$

$\sf x"=\dfrac{6-\sqrt{16}}{2}$

$\sf x"=\dfrac{6-4}{2}$

$\sf x"=\dfrac{2}{2}$

$\sf x"=1$