Question

alguem me pode ajudar
urgente

Answer 1

2)1/3(x-1)²=(-2/3x)-4

(x²-2x+1)/3=(-2x+12)/3
cancelando por três,
x²-2x+2x=12-1
x²=11
x=±√11

3)(-1-x)²=1-7x

(1²+2x+x²)=1-7x
x²+2x+7x+1-1=0
x²+9x=0
x'=0
e
x+9=0
x=-9
x"=-9

4)(9-x)(9+x)=100

81-x²=100
x²=81-100
x²= -19
x=±√-19
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x'=+4,3589i
e
x"=-4,3589i