Matemática, perguntado por gustavokoziell, 1 ano atrás

alguem me explica por favor ​

Anexos:

Soluções para a tarefa

Respondido por dougOcara
1

Resposta:

X+\left[\begin{array}{ccc}-3\\5\end{array}\right]=\left[\begin{array}{ccc}4\\-3\end{array}\right]\\\\\\X=\left[\begin{array}{ccc}x1\\x2\end{array}\right]\\\\\left[\begin{array}{ccc}x1\\x2\end{array}\right]+\left[\begin{array}{ccc}-3\\5\end{array}\right]=\left[\begin{array}{ccc}4\\-3\end{array}\right]

x1-3=4 => x1=4+3 => x1=7

x2+5=-3 => x2= -3-5 => x2= -8

X=\left[\begin{array}{ccc}7\\-8\end{array}\right]

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