Question

alguem me ajude porfavorr!!
a) 3^5.3^-7=
b)(2^3)^5=
c)20^x+1=
d)(a^+1)^3
e) [(x^5)^4]^3=
f)0,2=

Answer 1

$\boxed{3^5.3^{-7}~\to~3^{-2}}$

$\boxed{(2^3)^5~\to~2^{15}}$

$(20^{x+1}})$

$\boxed{(a^1)^3~\to~a^3}}$

$\boxed{(((x^{5}))^{4})^{3}~\to~x^{60}}$

$\boxed{0,2~\to~ \frac{1}{5} ~\to~5^{-1}}$