Question

Alguém me ajude por favor,

2m-3p=1
mp=2

Answer 1

$mp=2\Rightarrow m=\dfrac{2}{p} \\ 2(2/p)-3p=1 \\ 4/p-3p=1 \\ \dfrac{4-3p^2}{p}=1 \\ 3p^2+p-4=0$

$p\dfrac{-1\pm\sqrt{1^2-4\cdot3\cdot(-4)}}{2\cdot3}=\dfrac{-1\pm7}{6}$

$p'=1$ e $p''= -\dfrac{4}{3}$

$m'=\dfrac{2}{p'}=\dfrac{2}{1}=2$ e $m"=\dfrac{2}{p''}=\dfrac{2}{\frac{-4}{3}}=\dfrac{6}{-4}=-\dfrac{3}{2}$