Question

alguém me ajude a resolver pleasee!!!!!​

Answer 1

$\texttt{Ol\'a! :D}\\\rule{7cm}{0.01mm}$

Utilizaremos a seguinte expressão:

$\huge \underline{ \boxed{ \tt Q = m \cdot c \cdot \Delta \theta}}$

06:

$\large\tt Q = 500 \cdot 1 \cdot (70 - 30) \\ \large \underline{ \boxed{ \color{orangered}\tt Q =20000 \: cal}}$

07:

$\large\tt 20\,000 = 5000 \cdot c \cdot (80 - 50) \\ \large \tt c = \frac{2 \cancel0\,\cancel0\cancel0\cancel0} {15 \cancel0\,\cancel0\cancel0\cancel0} = \frac{2}{15} \\ \large \underline{ \boxed{ \color{orangered}\tt c \approx 0.13334\: { \tiny\frac{cal}{g \cdot \, ^{ \circ}C}}}}$

08:

$\large\tt - 1600 = 500 \cdot 0.217 \cdot (\theta_f - 80) \\ \large \tt 108.5\theta_f - 8680= - 1600 \\ \large \tt \theta_f = \frac{7080}{108.5} \\ \large \underline{ \boxed{ \color{orangered}\tt \theta_f \approx 65.25 \: ^{ \circ}C}}$

09:

$\large\tt Q = 400 \cdot 0.9 \cdot 50\\ \large \underline{ \boxed{ \color{orangered}\tt Q = 18\,000\: cal}}$

10:

$\large\tt 20\,000 = 600 \cdot c \cdot (60 - 30) \\ \large \tt c = \frac{20\,\cancel0\cancel0\cancel0}{18\, \cancel0\cancel0\cancel0} = \frac{10}{9} \\ \large \underline{ \boxed{ \color{orangered}\tt c \approx 1.112\: { \tiny\frac{cal}{g \cdot \, ^{ \circ}C}}}}$