Question

alguem me ajudar nessas duas questões já tentei muito e não consegui e tenho que entregar hoje a tarde​

Answer 1

$A = \left[ \begin{array}{cccc} 1 & -2 \\\\ 0 & 3 \end{array}\right]B = \left[ \begin{array}{cccc} 1 & -3 \\\\ 2 & 0 \end{array}\right]\\\\\\\\x=A^2+2B\\\\x=\left[ \begin{array}{cccc} 1 & -2 \\\\ 0 & 3 \end{array}\right]*\left[ \begin{array}{cccc} 1 & -2 \\\\ 0 & 3 \end{array}\right]+2\left[ \begin{array}{cccc} 1 & -3 \\\\ 2 & 0 \end{array}\right]$

$x=\left[ \begin{array}{cccc} 1.1-2.0 & 1.(-2)-2.3 \\\\ 0.1+3.0 & 0.(-2)+3.3 \end{array}\right]+2\left[ \begin{array}{cccc} 1 & -3 \\\\ 2 & 0 \end{array}\right]$

$x=\left[ \begin{array}{cccc} 1 & -8 \\\\ 0 & 9 \end{array}\right]+2\left[ \begin{array}{cccc} 1 & -3 \\\\ 2 & 0 \end{array}\right]$

$x=\left[ \begin{array}{cccc} 1 & -8 \\\\ 0 & 9 \end{array}\right]+\left[ \begin{array}{cccc} 2 & -6 \\\\ 4 & 0 \end{array}\right]$

$x=\left[ \begin{array}{cccc} 1+2 & -8-6 \\\\ 0+4 & 9+0 \end{array}\right]$

$x=\left[ \begin{array}{cccc} 3 & -14 \\\\ 4 & 9 \end{array}\right]$

Com isso, a operação $A^2+2B$ é igual a $x$