Question

alguem me ajudaaaaaa

(Números complexos) resolva em C as equações:

a) x2+7x+10=0

b) x2+2x+2=0

Answer 1

Resposta:

a) x2+7x+10=0

x'=[-7+√(49-40)]/2=(-7+7)/2=0

x''=[-7-√(49-40)]/2=(-7-7)/2=-7

b) x2+2x+2=0

x'=[-2+√(4-8)]/2=(-2+2i)/2=-1+i

x''=[-2-√(4-8)]/2=(-2-2i)/2=-1-i

Answer 2

Explicação passo-a-passo:

a) x² + 7x + 10 = 0

a = 1

b = 7

c = 10

∆ = b² - 4ac

∆ = 7² - 4 · 1 · 10

∆ = 49 - 40

∆ = 9

x = - b ± √∆ /2a

x = - 7 ± √9 /2 · 1

x = - 7 ± 3 /2

x¹ = - 7 + 3 /2 = - 4/2 = - 2

x² = - 7 - 3 /2 = - 10/2 = - 5

b) x² + 2x + 2 = 0

a = 1

b = 2

c = 2

∆ = b² - 4ac

∆ = 2² - 4 · 1 · 2

∆ = 4 - 8

∆ = - 4

x = - b ± √∆ /2a

x = - 2 ± √-4 /2 · 1

x = - 2 ± 2i /2

x¹ = - 2 + 2i /2 = - 1 + i

x² = - 2 - 2i /2 = - 1 - i