Question

Alguém me ajudaaaa por favooor

Answer 1

Resposta:

A

Explicação passo a passo:

log2 16

2^x=16

2^x=2^4

x=4

log4 32

4^x=32

(2^2)^x=2^5

2^2x=2^5

2x=5

x=5/2

log7 7

7^x=7^1

x=1

log0,2 125

0,2^x=125

(1/5)^x=125

(5^-1)^x=5^3

-x=3  (-1)

x=-3

log2 V8

2^x=V8

2^x=8^1/2

2^x=(2^3)^1/2

2^x=2^3/2

x=3/2

log∛4 1/√32

(∛4)^x=1/√32

(∛2^2)^x=(1/√2^5)

(2^2/3)^x=(1/2^5/2)

2^2x/3=2^-5/2

2x/3=-5/2

2x=-5/2.3

2x=-15/2

x=-15/2:2

x=-15/2.1/2

x=-15/4