Question

alguem me ajudaaa, por favorr, me ajudemmmmmmmmmmmm​

Answer 1

Resposta:

a) $\sqrt{5^{2} } = 5$

b) $\sqrt[3]{6^{3}} =6$

c) $\sqrt{2^{6}} =\sqrt{2^{2}*2^{2}*2^{2}} =2*2*2 = 8$

d) $\sqrt{4^{-8}} =\sqrt{(\frac{1}{4})^8} =\sqrt{(\frac{1}{4})^{2}*(\frac{1}{4})^{2}*(\frac{1}{4})^{2}*(\frac{1}{4})^{2}}$  $=(\frac{1}{4})*(\frac{1}{4})*(\frac{1}{4})*(\frac{1}{4})=\frac{1}{256}$

e) $\sqrt[5]{7^{10}} =\sqrt[5]{7^{5} *7^{5} } =7*7=49$