Question

alguém me ajuda por favor,rápido!!!!!

6x² + x - 1 = 0

e Também a

3x2 - 7x + 2 = 0​

Answer 1

$\boxed{x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}}$

1.

$6x^2+x-1=0\ \to\ a=6,\ b=1,\ c=-1$

$x=\dfrac{-1\pm\sqrt{1^2-4(6)(-1)}}{2(6)}=\dfrac{-1\pm\sqrt{25}}{12}=\dfrac{-1\pm5}{12}$

$\boxed{x=-\dfrac{1}{2}}\ \text{ou}\ \boxed{x=\dfrac{1}{3}}$

2.

$3x^2-7x+2=0\ \to\ a=3,\ b=-7,\ c =2$

$x=\dfrac{-(-7)\pm\sqrt{(-7)^2-4(3)(2)}}{2(3)}=\dfrac{7\pm\sqrt{25}}{6}=\dfrac{7\pm5}{6}$

$\boxed{x=\dfrac{1}{3}}\ \text{ou}\ \boxed{x=2}$