Question

alguem me ajuda pliss ​

Answer 1

Resposta:

${9a}^{2} {b}^{2}$

${49a}^{4} {b}^{2} {x}^{2}$

${25a}^{2} {b}^{2} {c}^{2}$

$1$

$\frac{64}{25} {x}^{4} {y}^{6}$

$- \frac{27}{8} {a}^{3} {b}^{6}$

$- \frac{1}{27} {a}^{9} {x}^{3}$

*Espero ter ajudado*