Question

Alguém me ajuda pfvr, só tenho até as 19 para poder responder.

Answer 1

a)10x=33

b)y=-2

a)5x/2-1/4=8

5x/2-1/4+1/4=8+1/4

5x/2=8+1/4

8+1/4=32+1/4=33/4=5x/2=33/4=4×5x/2=33

4×5x=33×2=4×5x=33×2

20x=33×2=20x=66

20x÷2=66÷2

10x=66÷2=10x=33

b)y/3+y+1/2=5/6+y/3+y+1/2-y=5/6+y-y

y/3+y+1/2-y=5/6=-2/3 y+y+1/2=5/6=

-4y+3(y+1)=5=-4y+3y+3=5=-y+3=5

-y=5-3=-y=2

-y=2=

y=-2