Question

alguém me ajuda pfvr​

Answer 1

Explicação passo-a-passo:

$2) \\ a)10 - \sqrt{49} + \sqrt[7]{0} = 10 - 7 + 0 = 3$

$b)5 \sqrt[3]{ - 8} + 12 - \sqrt[4]{81} = 5 \times - 3 + 12 - 3 = - 15 + 12 - 3 = - 6$

$c) \sqrt[8]{0} + \sqrt[9]{1} + \sqrt[4]{16} - \sqrt[3]{ - 64} = 0 + 1 + 2 - 4 = - 1$

$\sqrt[7]{ - 1} + \sqrt[3]{8} + \sqrt[5]{ - 32} + \sqrt{144} = - 1 + 2 - 2 + 12 = 11$

3)

$a) \sqrt[3]{5 {}^{2} } = 5 {}^{ \frac{2}{3} }$

$b) \sqrt[4]{2 {}^{3} } = 2 {}^{ \frac{3}{4} }$

$h) \sqrt{x} = x {}^{ \frac{1}{2} }$

$c) \sqrt{3} = 3 {}^{ \frac{1}{2} }$

$d) \sqrt[3]{5} = 5 {}^{ \frac{1}{3} }$

$e) \sqrt{10 {}^{3} } = 10 {}^{ \frac{3}{2} }$

$f) \sqrt[6]{9 {}^{5} } = 9 {}^{ \frac{5}{6} }$

$g) \sqrt[5]{a {}^{3} } = a {}^{ \frac{3}{5} }$