Question

alguém me ajuda pfvr​

Answer 1

Resposta:

a)

$\sf \dfrac{x}{3} = \dfrac{10}{6} \\\\6x = 3\times 10 \\6x = 30 \\\\x = \dfrac{30}{6} \\\\\framebox {\sf x =5}$

b)

$\sf \dfrac{x}{4} = \dfrac{91}{52} \\\\52x = 4 \times 91\\52x =364\\\\x = \dfrac{364}{52} \\\\\framebox {\sf x = 7 }$

c)

$\sf \dfrac{x}{7} = \dfrac{18}{21} \\\\21x = 7 \times 18 \\21 = 126 \\\\x = \dfrac{126}{21} \\\\\framebox { \sf x = 6 }$

d)

$\sf \dfrac{x}{30} = \dfrac{2}{105} \\\\30x = 2 \times 105 \\30x = 210 \\\\x = \dfrac{210}{30} \\\\\framebox {\sf x = 7}$

e)

$\sf \dfrac{x}{8} = \dfrac{36}{32} \\\\32x = 8 \times 36 \\\\32x = 288\\\\x = \dfrac{288}{32} \\\\\framebox { \sf x = 9 }$

f)

$\sf \dfrac{x}{3} = \dfrac{128}{48} \\\\48x = 3 \times 128\\\\48x = 384 \\\\x = \dfrac{384}{48} \\\\\framebox { \sf x = 8 }$

Explicação passo-a-passo: