Question

Alguem me ajuda pfv:

a) 10-5-2+3 =

b) 10-(5+2)+3=

c) (10-5)-(2+3)=

d) 10-(5-2+3)=

e) (17+9)-8-(11+4)=

f) 25 + {12+[2-(8-6)+2]}=

g) {[(18-3)+(7+5)-2]+5}-12=

h) 65-{30-[20-(10-1+6)+17=

i) 10+[4+(7x3+1)]÷3=

j) (7+2) x (3-1)=

k) [30+2x(5-3)]x2-10=

Valendo 20 Pontos

Answer 1

a. 6

b. 13 -7 = 6

c. 5 -5 = 0

d. 10 -6 = 0

e. 26 -8 -15 = 3

f. 25 {12 + (2 -2 +2)} = 25 +{12 +2} = 25 + 14 = 39

g. {[15 +10 ]+5} -12 = 30 -12 = 18

h. 65 + 17 -{30-[20-15]} = 65 -25 + 17 = 57

i. 10+26/3 = (30 + 26)/3 = 56/3

j. 9 *2 = 18

k 34*2 -10 = 58

Answer 2

a. 6

b. 13 -7 = 6

c. 5 -5 = 0

d. 10 -6 = 0

e. 26 -8 -15 = 3

f. 25 {12 + (2 -2 +2)} = 25 +{12 +2} = 25 + 14 = 39

g. {[15 +10 ]+5} -12 = 30 -12 = 18

h. 65 + 17 -{30-[20-15]} = 65 -25 + 17 = 57

i. 10+26/3 = (30 + 26)/3 = 56/3

j. 9 *2 = 18

k 34*2 -10 = 58