Question

Alguém me ajuda nessas questões por favor! Com toda conta de possível

Answer 1

$a)\frac{S\left(x\right)}{x}+2y+\frac{1=0eh\left(x\right)}{\left(x-3\right)^2}+\left(y-4^2\right)=25\\ e \frac{S\left(x\right)}{x}+2y+\frac{1=0eh\left(x\right)}{\left(x-3\right)^2}+\left(y-4^2\right)=25\\\\\\\frac{S\left(x\right)}{x}+2y+\frac{1=0eh\left(x\right)}{\left(x-3\right)^2}+\left(y-4^2\right)=25\\\\\\\mathrm{Verdadeiro\:para\:todo\:}y;\quad \frac{S\left(x\right)}{x}+2y+\frac{1=0eh\left(x\right)}{\left(x-3\right)^2}+y-4^2=25$

$b)s\left(x\right)\:\mathrm{de}\:\frac{S\left(x\right)}{x}-S\left(x\right)+\frac{2=0eh}{x^2}+S\left(x\right)^2=4:\quad S\left(x\right)\frac{-\left(x-x^2\right)+\sqrt{\left(x-x^2\right)^2-4x^2\left(\frac{2=0eh}{x^2}x^2-4x^2\right)}}{2x^2}\\\\\\\frac{S\left(x\right)}{x}-S\left(x\right)+\frac{2=0eh}{x^2}+S\left(x\right)^2=4\\\\\\\frac{S\left(x\right)}{x}x^2-S\left(x\right)x^2+\frac{2=0eh}{x^2}x^2+S\left(x\right)^2x^2=4x^2;\quad \:x\ne \:0$

$xS\left(x\right)-x^2S\left(x\right)+\frac{2=0eh}{x^2}x^2+x^2S\left(x\right)^2=4x^2;\quad \:x\ne \:0\\\\xS\left(x\right)-x^2S\left(x\right)+\frac{2=0eh}{x^2}x^2+x^2S\left(x\right)^2-4x^2=4x^2-4x^2;\quad \:x\ne \:0\\\\x^2S\left(x\right)^2+\left(x-x^2\right)S\left(x\right)+\frac{2=0eh}{x^2}x^2-4x^2=0;\quad \:x\ne \:0\\\\x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

$a=x^2,\:b=x-x^2,\:c=\frac{2=0eh}{x^2}x^2-4x^2:\quad S\left(x\right)_{1,\:2}=\frac{-\left(x-x^2\right)\pm \sqrt{\left(x-x^2\right)^2-4x^2\left(\frac{2=0eh}{x^2}x^2-4x^2\right)}}{2x^2}\\\\\\S\left(x\right)=\frac{-\left(x-x^2\right)+\sqrt{\left(x-x^2\right)^2-4x^2\left(\frac{2=0eh}{x^2}x^2-4x^2\right)}}{2x^2};\quad \:x\ne \:0\\\\\\s\left(x\right)=\frac{-\left(x-x^2\right)-\sqrt{\left(x-x^2\right)^2-4x^2\left(\frac{2=0eh}{x^2}x^2-4x^2\right)}}{2x^2};\quad \:x\ne \:0$$S\left(x\right)=\frac{-\left(x-x^2\right)+\sqrt{\left(x-x^2\right)^2-4x^2\left(\frac{2=0eh}{x^2}x^2-4x^2\right)}}{2x^2},\:S\left(x\right)=\frac{-\left(x-x^2\right)-\sqrt{\left(x-x^2\right)^2-4x^2\left(\frac{2=0eh}{x^2}x^2-4x^2\right)}}{2x^2}$

$c)\frac{S\left(x\right)}{3x}+\frac{y=0eh\left(x\right)}{\left(x+3\right)^2}+\left(y-3\right)^2=9:\frac{S\left(x\right)}{3x}+\frac{y=0eh\left(x\right)}{\left(x+3\right)^2}+\left(y-3\right)^2=9\\\\\\\frac{S\left(x\right)}{3x}+\frac{y=0eh\left(x\right)}{\left(x+3\right)^2}+\left(y-3\right)^2=9\\\\\mathrm{Verdadeiro\:para\:todo\:}y;\quad \frac{S\left(x\right)}{3x}+\frac{y=0eh\left(x\right)}{\left(x+3\right)^2}+\left(y-3\right)^2=9$

$d)\frac{S\left(x\right)}{4x}-\frac{3y=0eh\left(x\right)}{\left(x+1\right)^2}+\left(y-1\right)^2=9:\quad \mathrm{Verdadeiro\:para\:todo\:}y;\quad \frac{S\left(x\right)}{4x}-\frac{3y=0eh\left(x\right)}{\left(x+1\right)^2}+\left(y-1\right)^2=9$

$\frac{S\left(x\right)}{4x}-\frac{3y=0eh\left(x\right)}{\left(x+1\right)^2}+\left(y-1\right)^2=9$