Question

alguém me ajuda nessas contas por favor é pra hoje ​

Answer 1

Resposta:

Explicação passo-a-passo:

$a)(5x)*(-4x^2)=-20x^3\ \ \ \ \ \ b) (-2x)*(3x)=-6x^2\\c)(-n)*(6n)=-6n^2\ \ \ \ \ \ \ \ \ \ d)(-6x^2)*(3x^2)=-18x^4\\e)(-2y)*(5y)=-10y^2 \ \ \ \ \ \ \ f)(4x^2)*(5x^3)=20x^5\\g)(2y)*(-7y)=-14y^2\ \ \ \ \ \ \ h)(-2x)*(-3y)=6xy\\i)(3x)*(-5y)=-15xy\ \ \ \ \ \ \ j)(-3xy)*(-2x)=6x^2y$

$a)\frac{15x^6}{3x^2}=5x^4\ \ \ \ \ \ b)\frac{-30x^5}{3x^3}=-10x^2\\\\c)\frac{8x^6}{-2x^4}=-4x^2\ \ \ d)\frac{-35x^7}{5x^3}=-7x^4\\\\e)\frac{-14x^3}{2x^2}=-7x\ \ \ f)\frac{-10x^3y}{5x^2}=-2xy\\\\g)\frac{6x^2y}{-2xy}=-3x\ \ \ \ h)\frac{-7abc}{-ab}=7c\\\\i)\frac{15x^7}{6x^5}=\frac{5}{2}x^2 \ \ \ \ \ \ j)\frac{20a^3b^2}{y15ab^2}=\frac{4}{3}a^2$

Answer 2

Resposta

a)

$a){5x}^{4}$

$b) { - 10x}^{2}$

$c) { - 4x}^{2}$

$d) { - 7x}^{4}$

$e) - 7x$

$f) - 2xy$

$g) - 3xy$

$h)7c$

i) 15x^7/6x^5 = 3.5x^2 x^5/3.2x^5=

5x² /2

j) 4/3a²